You are given a 0-indexed array of integers nums of length n. You are initially positioned at nums[0].
Each element nums[i] represents the maximum length of a forward jump from index i. In other words, if you are at nums[i], you can jump to any nums[i + j] where:
0 <= j <= nums[i]andi + j < n
Return the minimum number of jumps to reach nums[n - 1]. The test cases are generated such that you can reach nums[n - 1].
Example 1:
Input: nums = [2,3,1,1,4] Output: 2 Explanation: The minimum number of jumps to reach the last index is 2. Jump 1 step from index 0 to 1, then 3 steps to the last index.
Example 2:
Input: nums = [2,3,0,1,4] Output: 2
Constraints:
1 <= nums.length <= 1040 <= nums[i] <= 1000- It's guaranteed that you can reach
nums[n - 1].
Solution:
# @param {Integer[]} nums
# @return {Integer}
def jump(nums)
n = nums.length
return 0 if n == 1
jumps = 0
farthest = 0
current_end = 0
(0...n-1).each do |i|
farthest = [farthest, i + nums[i]].max
if i == current_end
jumps += 1
current_end = farthest
return jumps if current_end >= n - 1
end
end
return jumps
end
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